# Complex Number Kookiness 6

## Examples:

(1 + i)(2 + 2i) = 4i

(1 + i)(7 + 7i) = 14i

(1 + i)(0 + 0i) = 0i

[Remember that any number multiplied by zero(0) is still zero!]

(1 + i)(101 + 101i) = 202i

(1 + i)(√(2) + i√(2)) = 2i√(2)

(1 + i)(π + πi) = 2πi ## This math trick works with all numbers; however, if you pick an imaginary or complex number for x, then... Well, look at the examples below to find out:

(1 + i)(i + i * i) = (1 + i)(i + i2) = (1 + i)(-1 + i) = -2

Let A = (1 + i); so, (1 + i)(A + Ai) = (1 + i) * 2i = -2 + 2i

Let B = (1 - i); so, (1 + i)(B + Bi) = (1 + i) * 2 = 2 + 2i

Since i2 = -1, it affected the 2nd complex number in these 3 final examples. Also, the real part of a complex number is usually printed to the left of the plus or minus sign in-between. (A minus sign means that the imaginary part is negative; if you see a minus sign to the left of the real part, then the real part is negative.)

## However, the final examples are still correct according to the formula at the top of this Web page! 